x^2-9x+18=0
So I'm gonna solve it as if you need to find the x values
So 18 is positive and 9 is negative, so we have to find 2 values that multiply to +18 but add to a -9
Which is negative 3 and negative 6. double - = +
(x-3) (x-6)
x intercepts ---> x= 3 x= 6
