solution:
Consider the curve: r(t) = t²i +(int)j + 1/t k
X= t² , y = int ,z = 1/t
Using, x = t², z = 1/t
X = (1/z)²
Xz²= 1
Using y = int, z= 1/t
Y = in│1/z│
Using x = t², y = int
Y = int
= in(√x)
Hence , the required surface are,
Xz² = 1
Y = in│1/z│
Y= in(√x)
