ImmortalFusedZamasu ImmortalFusedZamasu

01-08-2018
Mathematics

contestada

solve for y

A. 8

B.
[tex]3 \sqrt{7} [/tex]
C.
[tex]4 \sqrt{7} [/tex]
D. 12

solve for yA 8B tex3 sqrt7 texC tex4 sqrt7 texD 12 class=

Respuesta :

06-08-2018

Triangle ADC and triangle BCD are similar, therefore the sides are in proportion:

[tex]\dfrac{y}{9}=\dfrac{7}{y}[/tex]

cross multiply

[tex]y^2=9\cdot7\to y=\sqrt{9\cdot7}\\\\y=\sqrt9\cdot\sqrt7\\\\y=3\sqrt7[/tex]

Answer: B. 3√7

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