81^x^2 = 27^x
(3^4)^(x^2) = (3^3)^x
3^(4x^2) = 3^(3x)
4x^2 = 3x
4x^2 - 3x = 0
x(4x - 3) = 0
x = 0 oder x = 3/4
The solution to the equation 81^x^2=27^x is; x = 3/4
By indices;
[tex] {3}^{ {4x}^{2} } = {3}^{3x} [/tex]
Therefore;
Read more;
https://brainly.com/question/14637514
